DeepSky  -  continued

 

<Acceleration sequence>
v=(a-g)t,a-g=2 x 9.8-9.8=9.8m/s^2
v=v0=9.8t1
t1:period of acceleration(s)
h1=0.5 x 9.8 x t1^2=4.9 x t1^2
h1:altitude by acceleration(m)

<Inertial sequence>
v=v0-gt2, v2=v0/g
h2=v0 x t2 - 0.5 x g x t2^2
This case, ignored drug resistance, must be constructed too much rough simulation, that we need
recalculate later with trust F.
v0=9.8 x t1, h1=4.9 x t1^2
h1+h2=4.9(t1^2+t2^2)=30000(m)
t1^2+t2^2=30000/4.9, t1=v0/9.8=t2, 2(vo/9.8)^2=30000/4.9, v0=(30000 x 9.8 x 9.8/4.9 x 2)^(1/2)
v0=542.2m/s=1951.98km/h

<Trust estimate>
Then,in acceleration, object have motion according to dv/dt=((F-D0 x e^(-az)/(W0-bt)-1)g
Maximum velocity is denoted without effection of air resistence Vmax=((F/Wave)-1)g x tp
Substitute those values for this expression
F=2W1+0.5 x r0 x Cd x S x e^(-az)=2W1+0.5 x 1.23 x 0.34 x e^(-0.000133 x z0) x 542.2^2
  =2W1+7377.79          W1=W0-bt=craft weight + LES weight + booster empty weight